The Password Checker

Two rules, honestly enforced: eight characters and at least one digit. Nested conditionals and Boolean operators do the work. Be clear about what this is: a toy. Real password guidance lives in Staying Secure Online — and rule one is that you never type a real password anywhere for practice, including here.

The program

password = input("Invent a password (never type a real one!): ")
 
long_enough = len(password) >= 8
has_digit = False
 
for character in password:
    if character.isdigit():
        has_digit = True
 
if long_enough and has_digit:
    if password == "password1":
        print("Technically legal. Famously terrible.")
    else:
        print("Passed both checks. Not bad.")
else:
    if not long_enough:
        print("Too short - eight characters minimum.")
    if not has_digit:
        print("No digits - add at least one.")

Read it before you run it

Predict in writing first — then run the program and grade yourself.

• Which single input makes two complaint lines print at once?
• has_digit starts as False. What exactly can flip it to True — and is there anything that can ever flip it back?
• password1 passes both checks, yet gets insulted anyway. Which lines arrange that, and why must they sit inside the first if?

Make it yours

1. One line. Raise the minimum to twelve characters — then keep the complaint message honest.
2. A few lines. Add a third rule — at least one capital letter — using character.isupper() inside the existing loop.
3. A real change. Replace pass/fail with a strength score: one point per rule passed, reported as Strength: 2 out of 3.

Curriculum connection

C3.1

analyze existing code to understand the components and outcomes of the code

Link to original

C2.3

write programs that include single and nested conditional statements

Link to original